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Current Electricity

Question
CBSEENPH12037568

A resistance R is connected across a cell, of emf Ex and internal resistance rx. A potentiometer now measures the p.d. between the terminals of the cell, as V, state the expression for V in terms of E, rx and R.

Solution

We are given E, rx and R in series.
The equivalent resistance of the circuit is given by 
                      Requiv = R + rx 
Current flowing through the circuit , I = ER+rx 
Hence,
Voltage drop across R is given by ohm's law,
 
                             V=IR
                             
                               =ERR+rx 

                        V = E1+rxR  

which is the required relation.