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Current Electricity

Question
CBSEENPH12037558

A potentiometer wire has a length of 10 m and resistance 4Ω. An accumulator of emf 2 V and a resistance box are connected in series with it. Calculate the resistance to be introduced in the box so as to get a potential gradient of 0.1 V/m

Solution

Given,
Length of the potentiometer wire, l= 10 m
Resistance of the potentiometer wire, R = 
Emf of the accumulator connected in series with the wire, E = 2V
A resistance box in series is connected to the potentiometer wire.
Resistance of the resistance box - ?

i) Required potential gradient, k = 0.1 V/m

Potential drop along the potentiometer wire, V=k.l
=0.1 × 10  = 1 V

Therefore, current through the potentiometer wire,

                    I= VR = 14= 0.25 A 
Let, R' be the resistace of the resistance box then,
Using the relation,
                          I = ER+R' 0.25=24+R' 1 + 0.25 R' = 20.25 R' = 1R' = 4Ω 

Thus, a resiatance of 4Ω has to be introduced in the resistance box.