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Current Electricity

Question
CBSEENPH12037557
Wired Faculty App

Calculate the current drawn from the battery in the following network.

Solution

Emf of the circuit = 4 V
Resistors 1Ω, 5Ω and 4 Ω are in series.
∴ equivalent resistance, R1 = 1+5+4 = 10 Ω 

Now,
10Ω , 12 Ω and 2Ω are in parallel. 

Effective resistance =  12×1012+10 = 5.45 Ω 

5.45 and 2 are also in parallel.  

Therefore,
                  5.45×25.45+2= 1.46 Ω 

Using ohm's law,
                           V = IR 
This implies,
Current drawn from the circuit, I = VR = 41.46= 2.74 A 


Some More Questions From Current Electricity Chapter

What conclusion can you draw from the following observations on a resistor made of alloy manganin?

Current A

Voltage V

Current A

Voltage V

0.2

0.4

0.6

0.8

1.0

2.0

3.94

7.87

11.8

15.7

19.7

39.4

3.0

4.0

5.0

6.0

7.0

8.0

59.2

78.8

98.6

118.5

138.2

158.0

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