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Current Electricity

Question

A cylindrical metallic wire is stretched to increase its length by 5%. Calculate the percentage change in its resistance.

Solution

Given, the metallic wire is stretched such that, it's length increases to 5%.

Percentage change in length, dl/l = 5%

Resistance of wire is given by R = $ρ \frac{l}{A}$ = $ρ \frac{l^{2}}{V}$

Therefore, percentage change in the resistance of wire is given by,

$\frac{d R}{R} = 2 . \frac{d l}{l} = 2 \times 5 % = 10 %$

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Current Electricity

A cylindrical metallic wire is stretched to increase its length by 5%. Calculate the percentage change in its resistance.

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