-->

Current Electricity

Question

What will be the change in the resistance of Eureka wire, when its radius is halved and length is reduced to one-fourth of its original length?

Solution

Resistance is given by, R= $ρ \frac{l}{A}$ = $ρ \frac{l}{{πr}^{2}}$
Given,

r' = $\frac{r}{2}$ and
l' = $\frac{l}{4}$

Therefore,
New resistance, R' = $ρ \frac{\frac{l}{4}}{π \frac{r^{2}}{4}} = ρ \frac{l}{A}$

Implies, there is no change in resistance when radius is halved and length is reduced to one-fourth of it's original length.

For Daily Free Study Material Join wiredfaculty

Current Electricity

What will be the change in the resistance of Eureka wire, when its radius is halved and length is reduced to one-fourth of its original length?

Some More Questions From Current Electricity Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

Phone Number

Email Address

Loaction