Find the amount of work done in rotating an electric dipole of dipole moment 3 x 10^–3 cm from its position of stable equilibrium to the position unstable equlibrium in a uniform electric field of intensities 10⁴ NC^–1.

Solution

Given, dipole moment of an electric dipole, p= 3 x 10^–3Electric field intensity of dipole, E= 10⁴ NC^–1
Initially, dipole is in a stable equilibrium.
This implies, $θ_{1} = 0^{\circ}$

and, $θ_{2} = 180^{\circ} [dipole is in unstable equilibrium]$

Therefore,
Work done in rotating the dipole from an angle of θ₁ to θ_2,W = pE (cos θ₁ – cos θ₂)
W = 3 x 10^–3 x 10⁴ [1 – (– 1)]
= 60 J.

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Electrostatic Potential And Capacitance

Find the amount of work done in rotating an electric dipole of dipole moment 3 x 10^–3 cm from its position of stable equilibrium to the position unstable equlibrium in a uniform electric field of intensities 10⁴ NC^–1.

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Electrostatic Potential And Capacitance

Find the amount of work done in rotating an electric dipole of dipole moment 3 x 10–3 cm from its position of stable equilibrium to the position unstable equlibrium in a uniform electric field of intensities 104 NC–1.

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Find the amount of work done in rotating an electric dipole of dipole moment 3 x 10^–3 cm from its position of stable equilibrium to the position unstable equlibrium in a uniform electric field of intensities 10⁴ NC^–1.