Question
Given the resistances of 1 Ω, 2 Ω, 3 Ω, how will be combine them to get an equivalent resistance of (i) (11/3) Ω (ii) (11/5) Ω, (iii) 6 Ω, (iv) (6/11) Ω?
Solution
Given, three resistances 1Ω, 2Ω, 3Ω.
(i) Inorder to get an equivalent resistance of (11/3) Ω, join 1 Ω, 2 Ω in parallel and the combination in series with 3 Ω.
Reqivalent=
(ii) To get an equivalent resistance of (11/5)Ω, we must have a parallel combination of 2 Ω and 3 Ω in series with 1 Ω.
(iii) To get an equivalent resistance of 6 Ω, all resistors should be arranged in series.
Requivalent = 1+2+3= 6
(iv) All resistors should be arranged in parallel combination to have an effective resistance of (6/11) .
(iii) To get an equivalent resistance of 6 Ω, all resistors should be arranged in series.
Requivalent = 1+2+3= 6
(iv) All resistors should be arranged in parallel combination to have an effective resistance of (6/11) .
