A 500 μC charge is at the centre of a square of side 10 cm. Find the work done in moving a charge of 10 μC between two diagonally opposite points on the square.

Solution

The diagonally opposite points lie at equal distance from the centre of the sphere.
Let,
The distance from the centre of the square to opposite diagonal points be 'r'.
Opposite diagonal points be A and B
Therefore,
$V_{A} = \frac{1}{4 {πε}_{\circ}} \frac{500 \times 10^{- 6}}{r} a n d, V_{B} = \frac{1}{4 {πε}_{\circ}} \frac{500 \times 10^{- 6}}{r}$
Since, V_A=V_B there is no potential difference across A and B.
Hence, the work done in moving a charge is 0.

For Daily Free Study Material Join wiredfaculty

Electrostatic Potential And Capacitance

A 500 μC charge is at the centre of a square of side 10 cm. Find the work done in moving a charge of 10 μC between two diagonally opposite points on the square.

Some More Questions From Electrostatic Potential and Capacitance Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

Phone Number

Email Address

Loaction