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Electrostatic Potential And Capacitance

Question
CBSEENPH12037448

A proton placed in a uniform electric field of magnitude 2000 N/C moves between two points in the direction of electric field. If the distance between the points is 0.2 m, find value of (i) p.d. between the points (ii) work done.

Solution
Given, a proton is placed in uniform electric field and it moves between two points in the direction of electric field.
Magnitude of electric field, E= 2000 N/C
Charge on proton, q= 1.6 × 10-19 C
i) Potential differnce is given by, V= Ed
                                               =2000×0.2
                                               =400 V 
ii) Work done , W = qV
                         =1.6×10-19× 400=640×10-19 J

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