(i) Calculate the electric potential at a point X due to a charge of 0.5 μC located at 10 cm from it.
(ii) Also calculate the work done in bringing a charge of 3 x 10^–9 C from infinity to the point X.

Solution

Given,
Charge, q= 0.5 μC
Distance between point X and point charge, r=10 cm

i) Electric potential at X, V is given by
$\frac{1}{4 {πε}_{o}} . \frac{q}{r} = 9 \times 10^{9} \times \frac{0.5 \times 10^{- 6}}{10 \times 10^{- 2}} = 4.5 \times 10^{4} V$

ii) Amount of work done in bringing a charge of 3 $\times 10^{- 9} C$ from infinioty to X.
Work done = charge $\times$ potential at point X
= 3 $\times$ 10^-9 $\times$ 4.5 $\times$ 10⁴ = 13.5 $\times$ 10^-5 J

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(i) Calculate the electric potential at a point X due to a charge of 0.5 μC located at 10 cm from it.
(ii) Also calculate the work done in bringing a charge of 3 x 10^–9 C from infinity to the point X.

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(i) Calculate the electric potential at a point X due to a charge of 0.5 μC located at 10 cm from it. (ii) Also calculate the work done in bringing a charge of 3 x 10–9 C from infinity to the point X.

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(i) Calculate the electric potential at a point X due to a charge of 0.5 μC located at 10 cm from it.
(ii) Also calculate the work done in bringing a charge of 3 x 10^–9 C from infinity to the point X.