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Electrostatic Potential And Capacitance

Question

The electric potential at a point, distance 0.9 m, from a point charge is + 50 V. Find the magnitude and nature of the charge.

Solution

Assume, a point P from point charge 'q'.
Electrical potential, V=+50 V
distance between the charge and point P=0.9 m
We have to find the magnitude of charge q.
Potential is given by, V=

\frac{1}{4 {πε}_{o}} \frac{q}{r}

50 = 9 \times 10^{9} \times \frac{q}{0.9} \frac{50 \times 0.9}{9 \times 10^{9}} = q \Rightarrow q = + 5 \times 10^{- 9} C

The point charge is positive in nature.

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Electrostatic Potential And Capacitance

The electric potential at a point, distance 0.9 m, from a point charge is + 50 V. Find the magnitude and nature of the charge.

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