Electrostatic Potential And Capacitance

Question

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In a parallel plate capacitor, how is the capacity affected, when without changing the charge:
(i) the distance between the plates is doubled;
(ii) the area of the plate is halved.

Solution

Capacitance is given by $C = \frac{{Aε}_{o}}{d}$
where,
'A' is the area of plates and 'd' is the distance between plates.

(i) $As, C \propto \frac{1}{d};$ when distance between the plates is doubled, capacity is halved.
(ii) Since, C ∝ A; when area of plates is halved, capacity is also halved.

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Electrostatic Potential And Capacitance

In a parallel plate capacitor, how is the capacity affected, when without changing the charge:
(i) the distance between the plates is doubled;
(ii) the area of the plate is halved.

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For Daily Free Study Material Join wiredfaculty

Electrostatic Potential And Capacitance

In a parallel plate capacitor, how is the capacity affected, when without changing the charge:(i) the distance between the plates is doubled;(ii) the area of the plate is halved.

Some More Questions From Electrostatic Potential and Capacitance Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

In a parallel plate capacitor, how is the capacity affected, when without changing the charge:
(i) the distance between the plates is doubled;
(ii) the area of the plate is halved.