The separation between the plates of a charged capacitor is to be increased. Explain when work done will be more in case battery is removed after charging the capacitor or battery remains connected.

Solution

Capacitance is given by C=

\frac{ε_{\circ} A}{d}

\frac{Q}{V}

When, seperation between the plates of a charged capacitor increases, capacitance decreases.

Work done is given by W=Vd
where, V is the potential applied and d is the distance between the plates of capacitor.

Case 1: When, battery is removed, charge q remains constant and potential decreases.
Case 2: When, battery remains connected, potential remains constant and charge decreases.

Therefore, clearly more work is required to be done in the first case.

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Electrostatic Potential And Capacitance

The separation between the plates of a charged capacitor is to be increased. Explain when work done will be more in case battery is removed after charging the capacitor or battery remains connected.

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