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Electric Charges And Fields

Question
CBSEENPH12037239

Point charges having values + 1 μC, – 5 μC and + 2 μC are placed at the corners A, B and C respectively of an equilateral triangle of side 2 m in free space. Determine the magnitude of intensity at the point D midway between A and C.

Solution


Given, QA=1 μC=1×10-6 C, QB=-5μC=-5×10-6 C
QC=2μC = 2×10-6 C 
and, the side of an equilateral triangle= 2m


We have to find the magnitude of intensity at point D lying midway between A and C.

The intensity EA at D due to charge at A is given by


If E be the magnitude of the resultant intensity, then
   
E = 9×1032+15×1032 NC-1    = 1.749 × 104 NC-1