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Electric Charges And Fields

Question
CBSEENPH12037232

Two fixed point charges + 4e and + e units are separated by a distance a. Where should the third point charge be placed for it to be in equilibrium?

Solution
Let a point charge q be held at a distance x from the charge + 4e  in between the charges e and 4e.

∴ Distance of q from charge + e = (a – x)
Force on charge exerted by the charge + 4e is
 
  F1 = q (4e)4π 0 x2 [directed away from (4e)]

Force on charge q exerted by the charge + e is

  F2 = q(e)4π 0(a-x)2, [directed away from (e)]


For the charge q to be in equilibrium F
1 = F2

i.e.,            q (4e)4 π 0 x2 = q(e)4 π 0 (a-x)2

                         4x2 = 1(a-x)2       2x = 1a-x

                 x = 2a-2x

                            3x=2a  x = 2a/3

Hence the charge q should be held at a distance 2a / 3 from charge (+ 4e) and a/3 from charge (e).