Question
Two fixed point charges + 4e and + e units are separated by a distance a. Where should the third point charge be placed for it to be in equilibrium?
Solution
Let a point charge q be held at a distance x from the charge + 4e in between the charges e and 4e.
∴ Distance of q from charge + e = (a – x)
Force on charge exerted by the charge + 4e is
[directed away from (4e)]
Force on charge q exerted by the charge + e is
[directed away from (e)]
For the charge q to be in equilibrium F1 = F2
i.e.,
Hence the charge q should be held at a distance 2a / 3 from charge (+ 4e) and a/3 from charge (e).
∴ Distance of q from charge + e = (a – x)
Force on charge exerted by the charge + 4e is
[directed away from (4e)]
Force on charge q exerted by the charge + e is
[directed away from (e)]
For the charge q to be in equilibrium F1 = F2
i.e.,
Hence the charge q should be held at a distance 2a / 3 from charge (+ 4e) and a/3 from charge (e).