Question
A charge q is placed at the centre of the line joining two equal charges Q. Show that the system of three charges will be in equilibrium if q = – Q / 4.
Solution
Let two equal charges Q each, be held at A and B, where AB = 2x.
C is the centre of AB, where charge q is held, figure below.
Net force acting on q is zero. So q is already in equilibrium.
For the three charges to be in equilibrium, net force on each charge must be zero.
Now, total force on Q at B due to q and Q at A is
Hence proved.