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Electric Charges And Fields

Question
CBSEENPH12037291

Two identical charged bodies have 12 μC and – 18 μC charge respectively. These bodies experience a force of 48 N at certain separation. The bodies are touched and placed at the same separation again. Find the new force between the bodies.

Solution
When two identical bodies having different magnitude of charge are touched, the redistribution of charge takes place and both the bodies acquire same charge.

 Charge on each body after touching
                       
              = 12-182 = -3 μC

The new force between the bodies
                    F = 14πε03×10-6×3×10-6x2
but             48 = 14πε0.12 × 10-6 × 18 × μCx2

On dividing both the equations we get,
                      F = 48 × 3 × 10-6 × 3 × 10-612 × 10-6 × 18 × 10-6     = 48×3×312×18     = 2 N.

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