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Electric Charges And Fields

Question

If an oil drop of weight 3.2 x 10^–13 N is balanced in an electric field of 5 x 10⁵ Vm^–1, find the charge on oil drop.

Solution

Since the weight of an oil drop is balanced in an electric field we will have

$mg = qE \Rightarrow 3.2 \times 10^{- 13} \times 9.8 = q \times 5 \times 10^{5} \Rightarrow q = \frac{3.2 \times 10^{- 13} \times 9.8}{5 \times 10^{5}} \Rightarrow q = 6.272 \times 10^{- 18} C$

where, q is the charge on the oil drop.

Some More Questions From Electric Charges and Fields Chapter

a) An electrostatic field line is a continuous curve. That is, a field line cannot have sudden breaks. Why not?
b) Explain why two field lines never cross each other at any point?

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Electric Charges And Fields

If an oil drop of weight 3.2 x 10^–13 N is balanced in an electric field of 5 x 10⁵ Vm^–1, find the charge on oil drop.

Some More Questions From Electric Charges and Fields Chapter

a) An electrostatic field line is a continuous curve. That is, a field line cannot have sudden breaks. Why not?
b) Explain why two field lines never cross each other at any point?

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NCERT Sample Papers

Entrance Exams Preparation

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For Daily Free Study Material Join wiredfaculty

Electric Charges And Fields

If an oil drop of weight 3.2 x 10–13 N is balanced in an electric field of 5 x 105 Vm–1, find the charge on oil drop.

Some More Questions From Electric Charges and Fields Chapter

a) An electrostatic field line is a continuous curve. That is, a field line cannot have sudden breaks. Why not?b) Explain why two field lines never cross each other at any point?

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

If an oil drop of weight 3.2 x 10^–13 N is balanced in an electric field of 5 x 10⁵ Vm^–1, find the charge on oil drop.

a) An electrostatic field line is a continuous curve. That is, a field line cannot have sudden breaks. Why not?
b) Explain why two field lines never cross each other at any point?