Question
Suppose that the particle in Question 1.33 is an electron projected with velocity vx = 2.0 x 106 m s–1. If E between the plates separated by 0.5 cm is 9.1 x 102 N/C, where will the electron strike the upper plate? (|e| = 1.6 x 10–19 C, me = 9.1 x 10–33 kg.)
Solution
Given,
An electron is projected with velocity vx= 2.0.
Distance between the plates = 0.5 cm
Electric field between plates - =
Acceleration,
Using formula
We get,
Simplifying for value of t, we get
The electron covers a vertical distance which is given by