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Electric Charges And Fields

Question
CBSEENPH12037160

What is the net flux of the uniform electric field of question 1.15 through a cube of side 20 cm oriented so that its faces are parallel to the coordinate planes?

Solution
Given,

Electric field, E = 3 × 103 i^ NC-1
length of the sides of cube = 20 cm

 The area of each face out of the six faces of the cube = 20 x 20 = 400 cm2 = 4 x 10–2 m2.

The area vector of four faces of cube ABGH, OBGF, OCDF and ACDH is along +Y axis, –Z axis, –Y axis and +Z axis.
The direction of Electric field is along +X axis.
 S is perpendicular to each other so flux through there surfaces are zero.


Hence, the net electric flux through the cube

ϕ = E. S1 + E.  S2

Now,  S1 = S2 = 4×10-2m2 and the angle between E and S1 is 0°, whereas the angle between E and S2 is 180°
Thus,               
                   ϕ = E S1 cos 0°  +E S2 cos 180°   = E×4×10-2×1+E×4×10-2×(-1)    = 0

Now, it is established that if some electric flux enters the cube the same amount of flux leaves through the other face, so that the net flux is zero.