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Alternating Current

Question
CBSEENPH12047979

A series resonant LCR circuit has a quality factor ( Q-factor) 0.4. If  R = 2 kΩ,  C = 0.1 μF, then the value of inductance is

  • 0.1 H

  • 0.064 H

  • 2 H

  • 5 H

Solution

B.

0.064 H

The amplitude of the current is maximum at resonant frequency ω. The quantity factor is given by

      Q = ωoLR = 1ωoCR

where ωo = resonant frequency

Given:- R = 2kΩ = 2 × 103 Ω

            C = 0.1 μF = 0.1 × 10-6 F

The quantity factor Q defined by

            Q = 1R LC

            LC = (QR)2

∴          L = ( 0.4 × 2 × 103 )2 × 0.1 × 10-6

            L = 0.064 H