-->

Ray Optics And Optical Instruments

Question
CBSEENPH12047946

A 2.0 cm tall object is placed 15 cm in front of a concave mirror of focal length 10 cm. What is the size and nature of the image?

  • 4 cm, real

  • 4 cm, virtual

  • 1.0 cm, real 

  • none of these

Solution

A.

4 cm, real

        

According to new cartesian sign convention,

Object distance, u = -15 cm

Focal length of the concave mirror f = -10 cm

Height of the object h0 = 2 cm

According to mirror formula

               1v + 1u = 1f 

⇒             1v = 1f - 1u

⇒                  = 1-10 - 1-15

⇒             1v = 1-10+ 115

⇒              1v = 15 - 10- 150

⇒               v = - 30 cm

The image is formed at a distance of 30 cm from the mirror on the same side of the object. It is a real image.

Magnification of the mirror

                 m = - vu

                      = hIhO

⇒              - -30-15 = hI2

⇒                hI- 4cm

Negative sign shows that image is inverted. 

The image is real, inverted, of size 4 cm at a distance of 30 cm in front of the mirror.

Some More Questions From Ray Optics and Optical Instruments Chapter

In an optics experiment, with the position of the object fixed, a student varies the position of a convex lens and for each position, the screen is adjusted to get a clear image of the object. A graph between the object distance u and the image distance v, from the lens, is plotted using the same scale for the two axes. A straight line passing through the origin and making an angle of 45o with the x-axis meets the experimental curve at P. The coordinates of P will be

An experiment is performed to find the refractive index of glass using a travelling microscope. In this experiment distance are measured by 

Two lenses of power -15D and +5D are in contact with each other. The focal length of the combination is

The angle of incidence at which reflected light totally polarized for reflection from air to glass (refractive index n), is

If θ1 and θ2 be the apparent angles of dip observed in two vertical planes at right angles to each other, then the true angle of dip θ is given by

A beam of light from a source L is incident normally on a plane mirror fixed at a certain distance x from the source. The beam is reflected back as a spot on a scale placed just above the source L. When the mirror is rotated through a small angle θ, the spot of the light is found to move through a distance y on the scale. The angle θ is given by

A thin prism having refracting angle 10° is made of glass of refractive index 1.42. This prism is combined with another thin prism of a glass of refractive index 1.7. This combination produces dispersion without deviation. The refracting angle of second prism should be