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Semiconductor Electronics: Materials, Devices And Simple Circuits

Question
CBSEENPH12047937

The transfer ratio B of a transistor is 50. The input resistance of the transistor when used in the common emitter configuration is 2 kΩ. The peak value of the collector AC current for an AC input voltage of 0.02 V peak is

  • 200 μA

  • 0.01 mA

  • 0.25 mA

  • 500 μA

Solution

D.

500 μA

Given:-

β = 50,

R = 2 kΩ = 2 x 103 Ω

ΔVb = 0.02 V

ic = ?

Input current, 

               ibVbRb

                   = 0.022000

              ib = 10-5 A

Also, current gain is the ratio of collector current to the base current.

                    β = icib

 ∴             ic = β ib

                    = 50× 10-5 A

                ic = 500 × 10-6 A

                ic = 500 μA