Question
A body is moving along a rough horizontal surface with an initial velocity of 10 ms-1. If the body comes to rest after travelling a distance of 12m, then the coefficient of sliding friction will be
0.5
0.2
0.4
0.6
Solution
C.
0.4
Given:-
u = 10 ms-1
s = 12 m
v = 0
By third equation of motion,
v2 = u2 - 2 a s
Where v - final velocity
u - initial velocity
a - acceleration
s - dispalcement
0 = (10)2 - 2 × a × 12
24 a = 100
a = 4.17 ms-2
Coefficient of sliding friction is given by
μ =
=
μ = 0.41
