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Dual Nature Of Radiation And Matter

Question
CBSEENPH12047915

The graph 1λ and stopping potential (V) of three metals having work function ϕ1 , ϕ2 and  ϕ3 in an experiment of photoelectric effect is plotted as shown in the figure. Which one of the following statement is/are correct? [Here λ is the wavelength of the incident ray ]

     

(i) Ratio of work functions  ϕ1  :  ϕ2  :  ϕ3 = 1 : 2 : 4

(ii) Ratio of work functions ϕ1 :  ϕ2  : ϕ3 = 4 : 2 : 1

(iii) tanθ ∝ h ce, where h = Planck's constant, c = speed of light

(iv)The violet colour-light can eject photoelectrons from metals 2 and 3

  • (i), (iii)

  • (i), (iv)

  • (ii), (iii)

  • (i), (ii) and (iv)

Solution

A.

(i), (iii)

According to Einstein photoelectric equation,

       E = Kmaxϕ

        h cλ = ϕ + eVs

∴     Vs hcλ - ϕ  1e

   Vs versus 1λ graph is a straight line.

    Slope 

           tanθ = h ce

  The curves intersect the 1λ axis, where Vs is zero

∴   h cλ - ϕ = 0

⇒   1λ = ϕh c

For metal 1

      ϕ1h c = 0.001

For metal 2

       ϕ2hc = 0.002

For metal 3

         ϕ3hc = 0.004

∴   ϕ1 : ϕ2 : ϕ3 = 1 : 2 : 4

For metal 1

    λO1 = hcϕ = 10.001 = 1000 nm

For metal 2, threshold wavelength,

     λO2 = hcϕ = 10.002 = 500 nm

Simillarly, 

      λO3 = hcϕ = 10.004 = 250 nm

          λvoilet = 400 nm

 For metal 1     

    λvoilet < λthreshold

  For metal 3 

           λvoilet >  λthreshold

Some More Questions From Dual Nature of Radiation and Matter Chapter

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