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Ray Optics And Optical Instruments

Question
CBSEENPH12047913

A square wire of side 2.0 cm is placed 20 cm in front of a concave mirror of focal length 10 cm with its centre on the axis of the mirror and its plane normal to the axis. The area enclosed by the image of wire is

  • 7.5 cm2

  • 6 cm2

  • 2 cm2

  • 4 cm2

Solution

D.

4 cm2

Given:-

    square wire of side= 2 cm

    u = - 20 cm

    f = - 10 cm

Area of second wire = ?

∴   1v + 1u = 1f

     1v + 1-20 = 1-10

      1v = -110 + 120

        v = -20 cm

We know that,

       m = -vu

           = - -20-20

    m = -1

     Area of imageArea of object  = m2

        AiAo= -12

      Ai2 × 2 = 1

      Ai = 4 cm2