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Ray Optics And Optical Instruments

Question
CBSEENPH12047906

A fish rising vertically to the surface of water in a lake uniformly at the rate of 2 m/s observes a kingfisher diving vertically towards the water at a rate of 10 m/s. If refractive index of water n = 43 what will be the actual velocity of the kingfisher

  • 10 m/s

  • 8 m/s

  • 6 m/s

  • 9 m/s

Solution

C.

6 m/s

            

     Velocity of bird w.r t. fish

        v BF = 10 m/s

   and velocity of fish w.r.t. ground

       vBG = 2 m/s

∴   Distance between bird and fish, as seen by fish

       S = x + ny

on differentiating w.r.t. time, we get

       dSdt = dxdt + n dydt

⇒     10 = 2 + 43 vBG

⇒      vBG = vFG  +  n . vBG

⇒      10 = 2 + 43 vBG

⇒       vBG  = 843

⇒       vBG = 6m/s

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