A change of 8.0 mA in the emitter current brings a change of 7. 9 mA in the collector current. The value of a will be
0.96
0.93
0.90
0.99
D.
0.99
We have
IE = IB + IC
ΔIE = ΔIB + ΔIC
According to question,
ΔIE = 8.0 mA
ΔIC = 7.9 mA
∴ ΔIB = 8.0 mA - 7.9 mA
ΔIB = 0.1 mA
Now
Where IC is the current flowing into the collector terminal
IB is the current flowing into the base terminal
IE is the current flowing into the emitter terminal
=
= 0.99