A wire of resistance 10Ω is bent to form a complete circle. Find its resistance between two diametrically opposite point.

5 Ω

2.5 Ω

1.25 Ω

$\frac{10}{3}$ Ω

Solution

2.5 Ω

The wires ADC and ABC will have resistance 5 Ω each. These two are joined in parallel between A and C. The equivalent resistance R between A and C is, therefore give n by each. These two are joined in parallel between A and C. The equivalent resistance R between A and C is, therefore given by

R = $\frac{5 Ω \times 5 Ω}{5 Ω + 5 Ω}$

R = 2.5 Ω

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Current Electricity

A wire of resistance 10Ω is bent to form a complete circle. Find its resistance between two diametrically opposite point.

5 Ω

2.5 Ω

1.25 Ω

$\frac{10}{3}$ Ω

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Current Electricity

A wire of resistance 10Ω is bent to form a complete circle. Find its resistance between two diametrically opposite point. 5 Ω 2.5 Ω 1.25 Ω 103 Ω

Some More Questions From Current Electricity Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

A wire of resistance 10Ω is bent to form a complete circle. Find its resistance between two diametrically opposite point.

5 Ω

2.5 Ω

1.25 Ω

$\frac{10}{3}$ Ω