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Nuclei

Question

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Remaining quantity (in%) of radioactive element after 5 half lives is

4.125%

3.125%

31.1%

42.125%

Solution

B.

3.125%

Remaining quantity

N = N_o ${(\frac{1}{2})}^{n}$

= N_o ${(\frac{1}{2})}^{5}$

N = $\frac{N_{o}}{32}$

In percentage,

N = $\frac{N_{o}}{30 \times N_{o}} \times 100$

N = 3.125%

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