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Current Electricity

Question

Wired Faculty App

The equivalent resistance across A and B is

2 Ω

3 Ω

4 Ω

5 Ω

Solution

C.

4 Ω

The equivalent circuit can be redrawn as

We have

$\frac{p}{Q} = \frac{R}{S}$

$\frac{4}{4} = \frac{4}{4}$

So, the given circuit is a balanced Wheatstone's bridge.

Hence, the equivalent resistance

$R_{AB} = \frac{(4 + 4) \times (4 + 4)}{(4 + 4) \times (4 + 4)}$

= $\frac{64}{16}$

R_AB = 4 Ω

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