-->

Alternating Current

Question
CBSEENPH12047850

220 V, 50 Hz, AC source is connected to an inductance of 0.2 Hand a resistance of 20 Ω in series. Whatis the current in the circuit?

  • 3.33 A

  • 33.3 A

  • 5 A

  • 10 A

Solution

A.

3.33 A

From the formula

             I =  VR2 + ωL2

            I = 200202 + 2π × 50 × 0.22

           I = 20066

           I = 3.33 A