Question
The internal resistance of a primary cell is 42. It generates a current of 0.2 A in an external resistance of 21 n. The rate at which chemical energy to consumed in providing current is
1 J/s
5 J/s
0.42 J/s
0.8 J/s
Solution
A.
1 J/s
Rate energy
(But total Resistance R = 21 + 4 = 25 Ω)
So,