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Current Electricity

Question
CBSEENPH12047848

The internal resistance of a primary cell is 42. It generates a current of 0.2 A in an external resistance of 21 n. The rate at which chemical energy to consumed in providing current is

  • 1 J/s

  • 5 J/s

  • 0.42 J/s

  • 0.8 J/s

Solution

A.

1 J/s

Rate energy Ht = i2 R

(But total Resistance R = 21 + 4 = 25 Ω)

So,       Ht = 0.2 × 0.2 × 25

             Ht = 1 J/s