Question
Ionisation potential of hydrogen atom is 13.6 eV. Hydrogen atom on the ground state rarely excited by monochromatic radiation of photon 12.1 eV. The special line emitted by a hydrogen atom according to Bohr's theory will be
one
two
three
four
Solution
C.
three
En = eV
According to Bohr's model
E1 = -13.6 , E3 = -1.5
From the relation
E3 - E1 = (-1.5) - (-13.6)
= 12.09
E3 - E1 = 12.1 eV
As the energy is equal to the energy taken by n=1, n = 2, n=3 Hence there will be three spectral line.
