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Nuclei

Question
CBSEENPH12047841

A radioactive element  X23890 decays into Y 22283. The number of β-particles emitted are 

  • 1

  • 2

  • 4

  • 6

Solution

A.

1

     X83  238  Y 22283 

α - particles are emitted = 238 - 2224

                                    = 4

The atomic number is decreased 

                                 = 90 - 4 × 2 

                                  = 82

As the atomic number of Y 22283, so the atomic number is increased by 1, therefore, one β-particle is emitted.