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Dual Nature Of Radiation And Matter

Question
CBSEENPH12047832

A vessel of height 2 d is half filled with a liquid of refractive index 2  and the other half with a liquid of refractive index n (the given liquids are immiscible). Then, the apparent depth of the inner surface of the bottom of the vessel (neglecting the thickness of the bottom of the vessel) will be

  • nd n + 2

  • d n + 2n 2

  • 2 nd n + 2

  • ndd + 2n

Solution

B.

d n + 2n 2

The depth of the image of an object submerged in a transperent medium; it is reduced from the real depth of the object by a factor equal to the relative index of refraction of the medium with respect to air.

Refractive index μ = Real depth (d)Apparent depth (x)

For 1st liquid 

             2 = dx1

⇒            x1d2

Similarly, for 2nd liquid,

               n = dx2

⇒             x2dn

Total apparent depth = x1  + x2

                               = d2 + dn

                                = d n + 2n 2

The figure shows the apparent depth for (a) normal and (b) oblique viewing

Some More Questions From Dual Nature of Radiation and Matter Chapter

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