A current of 5A is passing through a metalic wire of cross-sectional area 4 × 10^-6 m² . If the density of charge carriers of the wire is 5 × 10²⁶ m^-3, then the drift velocity of the electrons will be

1 × 10² m/s

1.56 × 10^-2 m /s

1.56 × 10^-3 m/s

1 × 10^-2 m/s

Solution

1.56 × 10^-2 m /s

Drift velocity

V_d = $\frac{I}{neA}$

Where V_d is the drift velocity

I is the current

A is the cross-sectional area of the conductor

n is charge density (m^-3 ). This is the number of charge carriers that can move per m³.

$V_{d} = \frac{5}{(5 \times 10^{26}) \times (1.6 \times 10^{- 19}) \times (4 \times 10^{- 6})}$

⇒ = $\frac{1}{64}$

V_d = 1.56 × 10^-2 ms^-1

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