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Nuclei

Question
CBSEENPH12047816

Activity of a radioactive sample decreases to (1/3)rd of its original value in 3 days. Then, in 9 days its activity will become

  • (1/27) of the original value

  • (1/9) of the original value

  • (1/18) of the original value

  • (1/3) of the original value

Solution

A.

(1/27) of the original value

   R =Ro e-λt

⇒ 13 = e-λ × 3

        = e-3λ              ...(i)

Again 

    R'Ro = e-λ × 9

          = e-9λ

           =( e )3

           = 133

            = 127

     R' Ro = Ro27

Hence, in 9 days activity will become 127 of the original value.