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Nuclei

Question
CBSEENPH12047811

If 82U238 emits 8 α - particles and 6 β - particles, then the resulting nucleus is

  • 82U206

  • 82Pb206

  • 82U210

  • 82U214

Solution

B.

82Pb206

After one α-emission, the daughter nucleus reduces in mass number by 4 unit and in atomic number by 2 unit. In [β-emission the atomic number of daughter nucleus increases by 1 unit.

The reaction can be written as

U23892-8α X206 76  -6β  Y20682

Thus the resulting nucleus is  82Y206, i.e  82Pb206