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Electromagnetic Induction

Question
CBSEENPH12047803

In 0.1 s, the current in a coil increases from 1 A to 1.5A. If inductance of coil is 60 mH, then induced current in external resistance of 32 will be

  • 1 A

  • 0.5 A

  • 0.2 A

  • 0.1 A

Solution

D.

0.1 A

The magnitude of induced emf in a circuit is equal to the inductance × rate of current change and a circuit has an inductance of one Henry will have one volt induced in the circuit when the circuit changes at a rate of one ampere per second.

When a current in coil changes, it induces a back emf in the same coil. The self-induced emf is given by

Induced emf,

     e = L didt

           = 60 × 10-3 ×1.5  - 10.1

      e = 0.3 V

Induced current,

        i = eR

           = 0.33

       i  = 0.1 A

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