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Nuclei

Question
CBSEENPH12047786

Half-lives of two radioactive substances A and B are respectively 20 min and 40 min. Initially the samples of A and B have equal number of nuclei. After 80 min the ratio of remaining number of A and B nuclei is

  • 1 : 16

  • 4 : 1

  • 1 : 4

  • 1 : 1

Solution

C.

1 : 4

Total number of nuclei remained after n half- lives is 

             N = N12n

Total time given = 80 min

Number of half-lives of A, nA80 min20 min

                                           = 4

Number of half-lives of B, nB80 min40 min

                                           = 2

Number of nuclei remains undecayed

                    N =No 12n

Where No is initial number of nuclei.

             NANB = 12nA12nB

             NANB = 124122               =11614

                NANB = 14