When a charged particle moving with velocity $\vec{v}$ is subjected to a magnetic field of $\vec{B}$ induction , the force on it is non- zero. This implies that

angle between $\vec{v} and \vec{B}$ is necessarily 90^o

angle between $\vec{v} and \vec{B}$ can have any value other than 90^o

angle between $\vec{v} and \vec{B}$ can have any value other than 180^o

angle between $\vec{v} and \vec{B}$ is either zero or 180^o

Solution

angle between $\vec{v} and \vec{B}$ can have any value other than 180^o

When a charged particle q is moving in a uniform magnetic field $\vec{B}$ with velocity $\vec{V}$ such that angle between $\vec{V} and \vec{B}$ be θ, then due to an interaction between the magnetic field produced due to moving charge and magnetic force applied, the charge q experiences a force which is given by

F = qv sinθ

If θ = 0^o or 180^o

then sinθ = 0

∴ F = qvB sinθ

F = 0

Since, force on charged particle is non-zero, so angle $\vec{v} and \vec{B}$ between can have any value other than zero and 180°.

Note:- Force experienced by the charged particle is Lorentz force.

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