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Electrostatic Potential And Capacitance

Question

A charged particle (charge q) is moving in a circle of radius R with uniform speed v. The associated magnetic moments given by

$\frac{q ν R}{2}$

qνR²

$\frac{q ν R^{2}}{2}$

qνR

Solution

$\frac{q ν R}{2}$

As revolving charge is equivalent to a current, so

I = qf

$= q \times \frac{ω}{2 π} But ω = \frac{ν}{R}$

where R is radius of circle and v is uniform speed of charged particle.

μ = IA

= I × πR²

$μ = \frac{1}{2} qνR$