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Semiconductor Electronics: Materials, Devices And Simple Circuits

Question
CBSEENPH12047750

The total energy of an electron in the first excited state of hydrogen is about -3.4 eV. Its kinetic energy in this state is

  • -3.4 eV

  • -6.8 eV

  • 6.8 eV

  • 3.4 eV

Solution

D.

3.4 eV

The kinetic energy is equal to the negative of total energy.
Kinetic energy of electron

K = z e28 πεo rPotential energy of electron U = - 14πεo Ze2rTotal energy  E = K + U      = Z e28 πεor - Z e24 πεorE = -Ze28πεor

⇒ E  = - K

⇒  K = - E 

        = - ( - 3.4 )

K = 3.4 eV