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Nuclei

Question
CBSEENPH12047731

In the reaction,H12 +H13  He24 + n01 if the binding energies of H12,   13H  and   He24 are respectively a, b and c (in MeV), then the energy in this reaction is released in this reaction is

  • c + a - b

  • c - a - b

  • a + b + c

  • a +b - c

Solution

B.

c - a - b

The energy released per nuclear reaction is the resultant binding energy.

Binding energy of   H12  +  H13  = a + bBinding energy of  He24 = c

In a nuclear reaction, the resultant nucleus is more stable than the reactants. Hence, the binding energy of  He24  will be more than that of  H12 + H13

Thus, the energy released per nucleon

   = resultant binding energy

  = c - ( a+ b)

 = c - a - b