In the reaction given below ${}_{86}A^{222} \to {}_{84}B^{210}$ . How many α and β particles are emitted?

6α, 3β

3α, 4β

4α, 3β

3α,6β

Solution

3α, 4β

${}_{84}A^{222} \to {}_{84}B^{210} Decrease in mass number = 222 - 210 = 12 ∴ Number of α particles emitted = \frac{12}{4} = 3 {}_{86}A^{222} \to {}_{80}X^{210} \to {}_{84}B^{210}$

Increase in atomic number = 84 - 80 = 4

∴ Number of β particless emitted = 4

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Nuclei

In the reaction given below ${}_{86}A^{222} \to {}_{84}B^{210}$ . How many α and β particles are emitted?

6α, 3β

3α, 4β

4α, 3β

3α,6β

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When ₃Li⁷ nuclei are bombarded by protons, and the resultant nuclei are ₄Be⁸ , the emitted particles will be

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A photocell is illuminated by a small bright source placed 1 m away. When the same source of light is placed 1 /2 m away, the number of electrons emitted by photocathode would

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For Daily Free Study Material Join wiredfaculty

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In the reaction given below A22286 → B21084. How many α and β particles are emitted? 6α, 3β 3α, 4β 4α, 3β 3α,6β

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When 3Li7 nuclei are bombarded by protons, and the resultant nuclei are 4Be8 , the emitted particles will be

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Entrance Exams Preparation

In the reaction given below ${}_{86}A^{222} \to {}_{84}B^{210}$ . How many α and β particles are emitted?

6α, 3β

3α, 4β

4α, 3β

3α,6β

When ₃Li⁷ nuclei are bombarded by protons, and the resultant nuclei are ₄Be⁸ , the emitted particles will be