The light rays having photons of energy 1.8 eV are falling on a metal surface having a work function 1.2 eV. What is the stopping potential to be applied to stop the emitting electrons?
3 eV
1.2 eV
0.6 eV
1.4 eV
C.
0.6 eV
The stopping potential depends on the kinetic energy of the electrons, which is affected only by the frequency of incoming light and not by its intensity.
The maximum kinetic energy of the photoelectron
(KE)max = E - Φ =1.8-1.2
= 0.6 eV
i.e eVo = (KE)max
or eVo = 0.6 eV
∴ Stopping potential Vo = 0.6 V