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Dual Nature Of Radiation And Matter

Question
CBSEENPH12047700

If work function of a metal is 4.2 eV, the cut off wavelength is

  • 8000 Ao

  • 7000 Ao

  • 1472 Ao

  • 2950 Ao

Solution

D.

2950 Ao

The minimum energy needed by an electron to come out from a metal surface is called the work function of the metal.

Suppose the cutoff wavelength is represented by λo.

So, hcλo =work function=Wohcλo=4.2 ×1.6×10-19λo =6.6×10-34×3×1084.2×1.6×10-19  =2946×10-10 m λo  =2950 Ao

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