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Electric Charges And Fields

Question

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Taking the earth to be a spherical conductor of diameter 12.8×10³ km. Its capacity will be

711 μF

611 μF

811 μF

511 μF

Solution

711 μF

Here :- Diameter of earth =12.8×10³ km

$So radius R = \frac{12.8}{2} \times 10^{3} = 6.4 \times 10^{3} Km = 6.4 \times 10^{6} m Capacity C = 4 {πε}_{0} R = \frac{1}{9 \times 10^{9}} \times 6.4 \times 10^{6} = 711 \times 10^{- 6} = 711 μF$

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Electric Charges And Fields

Taking the earth to be a spherical conductor of diameter 12.8×10³ km. Its capacity will be

711 μF

611 μF

811 μF

511 μF

Some More Questions From Electric Charges and Fields Chapter

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NCERT Sample Papers

Entrance Exams Preparation

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For Daily Free Study Material Join wiredfaculty

Electric Charges And Fields

Taking the earth to be a spherical conductor of diameter 12.8×103 km. Its capacity will be 711 μF 611 μF 811 μF 511 μF

Some More Questions From Electric Charges and Fields Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

Taking the earth to be a spherical conductor of diameter 12.8×10³ km. Its capacity will be

711 μF

611 μF

811 μF

511 μF