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Wave Optics

Question

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20 kV potential is applied across X-ray tube, the minimum wavelength of X-ray emitted will be

0.62 A^o

0.37 A^o

1.62 A^o

1.31 A^o

Solution

0.62 A^o

(i)The minimum energy required to eject an electron from the surface is

called the photoelectric work function of the metal.

(ii)Energy greater than the work function of the metal (Φ_o)

required for electron emission from the metal surface can be supplied by suitably heating

(or) applying strong electric field or irradiating it by suitable frequency.

$From relation \frac{hc}{λ_{\min}} = eV \Rightarrow λ_{\min} = \frac{hc}{eV} = \frac{6.6 \times 10^{- 34} \times 3 \times 10^{8}}{1.6 \times 10^{- 19} \times 20 \times 10^{3}} λ_{\min} = 0.62 \times 10^{- 10} = 0.62 A^{o}$

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Wave Optics

20 kV potential is applied across X-ray tube, the minimum wavelength of X-ray emitted will be

0.62 A^o

0.37 A^o

1.62 A^o

1.31 A^o

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For Daily Free Study Material Join wiredfaculty

Wave Optics

20 kV potential is applied across X-ray tube, the minimum wavelength of X-ray emitted will be 0.62 Ao 0.37 Ao 1.62 Ao 1.31 Ao

Some More Questions From Wave Optics Chapter

In forward biased if the p-n junctions diode is forward biased, then width of potential barrier in p-n junction diode

In junction diode, the holes are because of

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

20 kV potential is applied across X-ray tube, the minimum wavelength of X-ray emitted will be

0.62 A^o

0.37 A^o

1.62 A^o

1.31 A^o